Thermofluids III homework Article

7-32A transformer that is 12 cm very long, 6. a couple of cm large, and your five cm large is to be cooled by attaching a 10-cm by six. 2-cm extensive polished aluminum heat sink (emissivity sama dengan 0. 03) to the top surface area. The heat sink has seven fins, that are 5 mm high, 2 mm thicker, and 12 cm very long. A fan produces air by 25°C seite an seite to the passages between the fins. The heat kitchen sink is to desolve 12 T of heat and the base temperature of the temperature sink can be not to exceed 60°C. Assuming the fins and the basic plate to become nearly isothermal and the the radiation heat copy to be negligible, determine the minimum free-stream velocity the fan should supply in order to avoid overheating. While using simplifying presumptions given in this problem, we really have a problem of 7 level plates with heat transfer from two sides. The spaces on the base in the fins also form toned plates. Thus we find the warmth transfer from flat plate with a total area of all of the fins as well as the unifnned surface area at the bottom of the fins. We have to operate this problem in reverse. We are essentially given the required heat copy – the 12W which the transformer must dissipate – and data on the fin area, and the temperature big difference. We can as a result compute heat transfer agent and operate backwards to find the air velocity. The level plates in cases like this have a length of 10 cm and a size of zero. 5 centimeter. The total area from one area of one very b is (0. 005 m)(0. 1 m) = 0. 0005 m2. There are 18 such edges giving an area of 0. 007 m2. Additionally , the total location at the top of the transformer is (0. 1 m)(0. 062 m) = 0. 0062 m2. The bases from the seven fins take up an area of 7(0. 1 m)(0. 002 m) sama dengan 0. 0014 m2. As a result the unfinned area within the base is the difference in these areas: 0. 0062 m2 – 0. 0014 m2. sama dengan 0. 0048 m2. The total area pertaining to the air is definitely the sum in the fin place and the unfinned area: zero. 007 m2 + 0. 0048 m2 = 0. 0118 m2. From these types of area data and the additional given data we can figure out the heat copy coefficient the following.

We need surroundings properties to...

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